Cos 2x + 3sinx-2 = 0

25 мая 2019 Хагалль ответил: Решение: cos^2х-sin^2х+сos^2х+sinхcosх=0 2cos^2х-sin^2х+sinхcosх=0 Делим все части уравнения на cos^2х, получаем 2-tg^2х+tgх=0 Заменим tgх=у Получим у^2-у-2=0. Д=9. у1=2 и у2=-1 Далее tgх=2 и tgх=-1 х1=arctg2+nП и х2=-П/4+nП

Take the inverse cosine of both sides of the equation to extract from inside the cosine. The exact value of is . Chú ý. Nếu các bạn đăng kí thành viên mà không nhận được email kích hoạt thì hãy kiểm tra thùng thư rác (spam).

16.04.2021

2(1-sin^2x) +3 sinx = 0-2sin^2x +3sinx +2 = 0. sinx = {-3 +/- 5}/-4. sin x = -8/-4 = 2 which is impossible and is rejected. sinx = 2/-4 = -1/2. x = arcsin(-1/2) which gives solutions in quadrants III & IV. Each solution has additional solutions by adding or subtracting 2npi where n is any integer. X^3-3X+1=0 2 . X^3-X-2=0 3.

You can put this solution on YOUR website! 3-3sinx-2cos^2x=0 3-3sinx-2 2sin^2x=0 2sin^2x-3sinx 1=0 2sinx(sinx-1)-(sinx-1)=0 (sinx-1)(2sinx-1)=0 sinx=1,sinx=1/2 x=90 or 30

The exact value of is . Chú ý.

Cos 2x 3 Cos X- -2 17) Sin 2x Cos X + Cos 2x Sin X =-1 Find All Solutions, 4 cos ?= 2 22. cos x + 3 = 4 sin x 21. 3sinx-2=0 24. sin 2x=- 3) sin2x + 3 sin x-1 = 0

2 x = 5π. 2 sin2x. 2cosx. [0,3π] x = π. 2 x = 3π.

Example 24 Solve 2 cos2 x + 3 sin x = 0 2 cos2x + 3 sin x = 0 2 (1 − sin2 x) + 3 sin x = 0 2 – 2 sin2x + 3 sin x = 0 –2sin2x + 3sin x + 2 = 0 Let sin x = a So, our equation becomes sin2 x + cos2 x = 1 cos2 x = 1 – sin2 x –2a2 + 3a + 2 = 0 0 = 2a2 – 3a – 2 2a2 – 3a – 2 = 0 2a2 – 4a + a – 2 = 0 2a (a – 2) + 1 (a – 2) = 0 (2a + 1) (a – 2) = 0 Hence 2a + 1 Chú ý. Nếu các bạn đăng kí thành viên mà không nhận được email kích hoạt thì hãy kiểm tra thùng thư rác (spam). Nếu không biết cách truy cập vào thùng thư rác thì các bạn chịu khó Google hoặc đăng câu hỏi vào mục Hướng dẫn - Trợ giúp để thành viên khác có thể hỗ trợ.

Help find the general solution to:sin^2x-3cosx+sinxcosx-3sinx=0 . calculus. Show that 3sin(2x)-2cos(x)=0 Math Multiply then use fundamental identities to simplify the expression below and determine which of the following is not equivalent (2 - 2cos x)(2 + 2cos x) a.4 - 4cos^2 x b . 4 - cos^2 x c.4/(1 + cot^2 x) d. 4sin^2 x e.4/(csc^2 x) You can put this solution on YOUR website!

3. (sin x)2 = 1. 2. (1 - cos 2x) . 4. (secx)2 = (tan x)2 + 1.

X^3-3X+1=0 2 . X^3-X-2=0 3. 2X-3SINX=0 . PreCalc.

√2 cos^2 5x=cos5x ; 4.

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Solution for Cos^2x+3sinx-3=0 equation: Simplifying Cos 2 x + 3sinx + -3 = 0 Reorder the terms: -3 + 3insx + os 2 xC = 0 Solving -3 + 3insx + os 2 xC = 0 Solving for variable 'i'. Move all terms containing i to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3insx + 3 + os 2 xC = 0 + 3 Reorder the terms: -3 + 3 + 3insx + os 2 xC = 0 + 3 Combine like terms: -3

X^3-3X+1=0 2 . X^3-X-2=0 3. 2X-3SINX=0 . PreCalc. Sqrt of 9sin^2x Is the answer |3sinx|?

You can put this solution on YOUR website! solve cos^2x-3sinx=3 where 0 x / 2 pi cos^2(x)-3sinx=3 1- sin^2(x)-3sinx-3=0 - sin^2(x)-3sinx-2=0 sin^2(x)+3sinx+2=0 (sinx+2)(sinx+1)=0.. sinx+2=0 sinx=-2 (reject(-1 ≤ x ≤1))

so either 2sin x - 1 = 0 ==> sin x = 1/2 ==> x = pi/6 + 2pi*n or. x = 5pi/6 + 2pi*n (n is an integer) or sin x - 1 = 0 ==> sin x = 1 ==> x = pi/2 + 2pi*n. general solutions: x = pi/6 S={pi/6 +2pin, (5pi)/6 +2pin, x=pi/2+2pin} Use Double Argument Property: cos2A=1-2sin^2A 1-2sin^2x+3sinx-2=0 2sin^2x-3sinx+1=0 (2sinx-1)(sinx-1)=0 2sinx-1=0 or sinx-1 Giải phương trình sau: cos 2x - 3sin x - 2 = 0 .

1−2sin2x+3sinx−2=0. 2sin2x−3sinx+1=0. 16 Oct 2015 0:00 / 5:36.